Chapter 9 – Rational Equations and Functions
May 11th, 2011 by corricelli
Hello Team 8,
Please use this spot to post questions/advice/etc related to Chapter 9!
Happy blogging,
Mrs. Corricelli
7 Responses to “Chapter 9 – Rational Equations and Functions”
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Hey guys! i found these really good practice problems and little tips to help with this section! so if you want some more practice before the quiz on friday go to these sites!
http://www.kutasoftware.com/FreeWorksheets/Alg1Worksheets/Adding+Subtracting%20Rational%20Expressions.pdf
http://teachers.henrico.k12.va.us/math/hcpsalgebra2/Documents/9-4/Addsubrationalexp9_4.pdf
http://teachers.henrico.k12.va.us/math/hcpsalgebra2/Documents/9-4/9_4_HW.pdf
http://teachers.henrico.k12.va.us/math/hcpsalgebra2/Documents/9-4/FlowChart.pdf
Wonderful, Lilah!!!
Thanks so much!
Go team 8 – who knows? Maybe we can get to 80% participation tonight???
Happy blogging/quiz prep,
Mrs. Corricelli
Hi! I had a question on number 13 on the 9.5 practice b worksheet. I’m not quite sure what exactly I’m doing wrong, but I’m getting very weird numbers…I start off by multiplying each denominator by the other fractions it’s being added or subtracted too. So, I’m multiplying (1/3x) X (x+2) and 1 by (x+2), and so on. If anyone has any tips it would be very helpful! Thanks!
hey, im having trouble on number 7 for 9.5, i cant find a common denominator for all 3 fractions. im stuck at 4x-2/xsquared+4/x+3. can anyone help
Casey and Atticus,
Way to contribute!
Casey, I do not have your problem in front of me. Can anyone specify it?
Atticus, 4x-2/xsquared+4/x+3 = 4x/1-2/(x^2)+4/(x+3), I assume?
If I am correct, then the common denominator will be the least amount of work to include 1, x^2, and x+3 in all denominators. Since none of these are factors of the other, you have no choice but to use x^2(x+3) as the denominator.
Hope this helps!
Mrs. Corricelli
casey, when you get the denominator of the problem, x/x+2 + 1/x, with a common denominator you can cancel it out because it ends up being x+2/x+2 so the rest is just the algebra in the numerator( x+2)-4(3x)/3x(x+2).
On the work/rate problems w.s we got in class today i dont understand how you got 120 as the number you multipy by. i got X/6 + X/8 + X/10 and i thought you just multiply across to get the number you mult. but thats not the case. so i guess my question is how do you find the number you mult. by when you have 3 of the X over a number?