Section 8 (Applications & Models)
Nov 6th, 2010 by corricelli
Hello Teams 2 and 7,
Let’s use this spot to post questions for Honors Precalculus, Unit 4, Section 8!
Happy blogging,
Mrs. Corricelli
10 Responses to “Section 8 (Applications & Models)”
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For #63 on the homework, it asks to graph.
I used 1/4 as the amplitude, becaue the equation is 1/4cos…
3 was given as the maximum displacement value. I’m a little confused on how this factors in to the graph, or the the problem in general. Does anyone know? At first I thought it had to do with amplitude but now I am not sure
Mrs. Corricelli,
I have absolutely no idea how to even start number 43 on tonight’s homework. Do you have any hints?
Joe:
For 43, you put it into y= mx + b for the two lines, in order to get the slope of the lines. Then use the slopes in the equation and plug in what you got into arctan(answer of equation) to get alpha. Hope this helps!
Haley:
You’re right, the max/ min displacement is the amplitude (for this equation; for others, I’m not exactly sure). Notice that y is in feet, and it’s 3″. 1/4 feet= 3 inches. It’s still the same.
cheers.
I don’t understand how you can use the distance formula for the problems we did in class, like 37b in the homework. I just found the new bearing by using arctan and then used that angle into a trig function to find d. Will I still get the same answer?
Joe
to start 43 you change the lines into y=mx+b form so you know the slope. Then you plug the two slopes into the equation given and solve. You should get tan(symbol)=5. From there you use the inverse of tan to find the symbol. I hope that helps.
Oo sorry I didn’t see the post answering your queation.
Sorry, maybe I’m totally blanking, but how do you find the angles A and B for number 11 on the homework?
Tiana,
For angle A you should use arccos(16/52) and angle B should be arcsin(16/52). You use arc___ to find the angle measure.
Hope this helps!
Tiana,
See the figure.
Mariah,
Did you check in the back of the book?